2[d+3]=d+12

Solution for 2[d+3]=d+12 equation:

Simplifying
2[d + 3] = d + 12

Reorder the terms:
2[3 + d] = d + 12
[3 * 2 + d * 2] = d + 12
[6 + 2d] = d + 12

Reorder the terms:
6 + 2d = 12 + d

Solving
6 + 2d = 12 + d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1d' to each side of the equation.
6 + 2d + -1d = 12 + d + -1d

Combine like terms: 2d + -1d = 1d
6 + 1d = 12 + d + -1d

Combine like terms: d + -1d = 0
6 + 1d = 12 + 0
6 + 1d = 12

Add '-6' to each side of the equation.
6 + -6 + 1d = 12 + -6

Combine like terms: 6 + -6 = 0
0 + 1d = 12 + -6
1d = 12 + -6

Combine like terms: 12 + -6 = 6
1d = 6

Divide each side by '1'.
d = 6

Simplifying
d = 6